Width of one of the two slits in a Young's double slit interference experiment is half of the other slit. The ratio of the maximum to the minimum intensity in the interference pattern is:
A
3 : 1
B
C
9 : 1
D
Text Solution
Verified by ExpertsThe correct answer is:
D
In Young's double-slit interference experiment, the width of one slit is half that of the other. The intensity, I, is proportional to the slit width. This gives us:
The maximum intensity, 
, occurs when the amplitudes add constructively:
The minimum intensity, 
, occurs when the amplitudes interfere destructively:
Now, using 
and 
, we find:
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